The van ’t Hoff factor of $H g_{2} C l_{2}$ in its aqueous solution will be $(H g_{2} C l_{2}$ is 80% ionized in the solution):

1.6

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2.6

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3.6

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4.6

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Solution

The correct option is B 2.6
$H g_{2} C l_{2} ⇌ H g_{2}^{2 +} + 2 C l^{-}$
n = 3
$α$ = $\frac{i - 1}{n - 1}$
$0.8$ = $\frac{i - 1}{3 - 1}$
i = 2.6

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