wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The vapour density of a mixture consisting of NO2 and N2O4 is 38.3 at 26.7oC. Calculate the number of moles of NO2 in 100g of the mixture.

Open in App
Solution

The vapour density of a gas is the density of that gas relative to that of hydrogen gas,
Thus,
Vapour density=(densityofNO2N2O4mixture)(densityofH2gas)

Vapour density =(massofNO2N2O4mixture)(massofH2gas)

Vapourdensity=(molarmassNO2N2O4mixture)(molarmassofH2gas)

Vapour density =(molarmassNO2N2O4mixture)2

Molar massNO2N2O4mixture= Vapourdensity×2

=38.3×2

=76.6gmol1

Let the percentage of NO2 gas be x, the percentage of N2O4 gas be 1-x

x(molarmassofNO2gas)+(1x)(molarmassofN2O4)=76.6

x(46)+(1x)(92)=76.6
x=33.48

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Pascal's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon