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Mole Concept

The vapour de...

Question

The vapour density of a mixture containing $N O_{2}$ and $N_{2} O_{4}$ is $38.3$ . The number of moles of $N O_{2}$ in a $100$ g mixture is (write numerical value upto 2 digits only after decimal point like for 0.19, write 19) :

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Solution

Given vapour density of mixture = $38.3$
$∴ M o l a r m a s s o f m i x t u r e = 2 \times 38.3 = 76.6$
Let $a$ g of $N O_{2}$ be present in $100$ g mixture,
$∴ g o f N_{2} O_{4} i n m i x t u r e = (100 - a)$
Therefore, $\frac{a}{46} + \frac{100 - a}{92} = \frac{100}{76}$
$∴ a = 20.10 g$
$∴ M o l e o f N O_{2} i n m i x t u r e = 20.10 / 46 = 0.44$
So, answer is $44$ .

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