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Mixture

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Question

The vapour density of a mixture containing $N O_{2}$ and $N_{2} O_{4}$ is $38.3$ at $27^{o} C$ . Calculate the moles of $N O_{2}$ in $100$ g of the mixture.

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Solution

Mol mass of mixture $= 2 \times 38.3 = 76.6$

No. of moles in 100 g of mixture $= \frac{100}{76.6}$

Let a g of $N O_{2}$ is present in mixture.

$M o l e s o f N O_{2} + M o l e s o f N_{2} O_{4} = M o l e s o f m i x t u r e$

$\frac{a}{46} + \frac{100 - a}{92} = \frac{100}{76.6}$ "or" $a = 20.10 g$

Moles of $N O_{2}$ in mixture $= \frac{20.10}{46} = 0.437$

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