The vapour density of a mixture having a molecular weight $224 g / m o l$ at $N T P$ is :

0.01

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10

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112

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2

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Solution

The correct option is C $112$
$M o l e c u l a r w e i g h t = 2 \times v a p o u r d e n s i t y$ at $N T P$ .
Vapour density is the density of a vapour in relation to that of hydrogen. It may be defined as mass of a certain volume of a substance divided by mass of same volume of hydrogen.
The molecular weight of the substance here is $224 g / m o l$ .
$∴$ vapour density $= \frac{224}{2} = 112$ .

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The vapour density of a mixture having a molecular weight 224g/mol at NTP is :

The vapour density of a mixture having a molecular weight $224 g / m o l$ at $N T P$ is :