Question

The vapour pressure of a mixture of two volatile liquids is expressed as $P_m=6.0+1.5X_B$, where, $X_B$ is mole fraction of $B$ is a mixture. The vapour pressure of $A$ at the same temperature is:

Answer 1

since we have, vapour pressure for two volatile liquids as

$P_{total}=P_A^0{x}_A+P_B^0{x}_B$

vapour pressure is given as $P_m=6.0+1.5X_B$

so, on equating the two equations we get,

vapour pressure of A = $6$