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Question

The vapour Pressure of acetone at 20C is 185 torr. When 1.2 g of a non- volatile substance was dissolved in 100g of acetone at 20C, its vapour pressure was 183 Torr. The molar mass of the substance is

A
32
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B
64
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C
128
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D
488
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Solution

The correct option is B 64
p0=185 Torr at 20C
ps=183 Torr at 20C
Mass of non- volatile substance, m = 1.2 g
Mass of acetone taken = 100g
M = ?
As, we have p0psps=nN
Putting the values, we get,
1851831831.2M100582183=1.2×58100×M
M=183.1.2×582×100
M=63.684=64g/mol

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