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Question

The vapour pressure of pure liquids 1 and 2 are 450 mm Hg and 700 mm Hg respectively at 350 K.
When total vapour pressureof the solution is 600 mm Hg, the mole fraction of component 1 in liquid phase will be:

A
0.4
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B
0.7
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C
0.3
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D
0.6
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Solution

The correct option is A 0.4
By Raoult's Law :
PT=p1χ1+p2χ2
where
PT is the total pressure of the solution.
p1 is the vapour pressure of pure component 1
p2 is the vapour pressure of pure component 2
χ1 is the mole fraction of component 1 in liquid phase.
χ2 is the mole fraction of component 2 in liquid phase.

Putting the values:
600=450χ1+700χ2600=450χ1+700(1χ1)600=700250χ1χ1=0.4
χ2=10.4=0.6
Hence option (a) is correct

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