You visited us 3 times! Enjoying our articles? Unlock Full Access!

Percentage Composition

The vapour pr...

Question

The vapour pressure of pure water at $26^{\circ} C$ is 25.21torr. What is the vapour pressure of a solution which contains 20.0g of glucose in 70g of water?

27.9torr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25.9torr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24.5torr

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

32.0torr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 24.5torr
$n_{1} = \frac{20}{180} = 0.111; n_{2} = \frac{70}{18} = 3.89$
$\frac{P_{0} - P_{S}}{P_{0}} = \frac{n_{1}}{n_{1} + n_{2}}$
$\frac{25.21 - P_{S}}{25.21} = \frac{0.111}{0.111 + 3.89} = 0.0277$
$25.21 - P_{S} = 0.0277 \times 25.21 = 0.699$
$P_{S} = 25.21 - 0.699 = 24.5 t o r r$

Suggest Corrections

Similar questions

26^{\circ} C

C_{6} H_{12} O_{6}

^{o}

_{6}

_{12}

_{6}

18 g of glucose is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100º C is:

P_{A}^{0}

P_{B}^{0}

300 K

600 t o r r

1.5

0.5

P_{B}^{\circ}

Join BYJU'S Learning Program