The vapour pressure of water at 23^°C is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

19.602

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

19.402

No worries! We‘ve got your back. Try BYJU‘S free classes today!

19.202

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 19.602

Suggest Corrections

Similar questions

Q. The vapour pressure of water at

23^{o} C

is 19.8 mm. 0.1 mole glucose is dissolved in 178.2 g water. What is the vapour pressure (in mm) of the resultant solution?

Q. The vapour pressure of water at

23^{0} C

is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant solution?

The vapour pressure of water at 23^°C is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant.

Q. 18 g of glucose is dissolved in 178.2 g of water. The vapour pressure of the solution at

100^{o} C

is :

(vapour pressure of pure water at

100^{o} C

is 760 mm Hg)

Q. The vapour pressure of water at

20^{C}

is 17.5 mm Hg. If 18 g of glucose

(C_{6} H_{12} O_{6})

is added to 178.2 g of water at

20^{\circ} C <

the vapour pressure of resulting solution will be _

Join BYJU'S Learning Program

The vapour pressure of water at 23°C is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant.

The correct option is B 19.602

The vapour pressure of water at 23^°C is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant.