Question

The vapour pressure of water at 300 Kelvin in a closed container is 0.48 atm if the volume of container is doubled it vapour pressure at 300 Kelvin will be________

Answer 1

initial vapour pressure = 0.48atm

Let the initial volume be V

The final volume = 2V

P1V1= P2V2

P2 = (0.48×V)÷2V
= 0.24 atm