Question

Two container A and B are partly filled with water and closed. The volume of A is twice that of B and it contains half the amount of water in B. If both are at same temperature, the water vapour in the container will have pressure in the ratio of?

• A. $1:2$
• B. $1:1$
• C. $2:1$
• D. $4:1$

Answer 1

Answer: (A)

$1:2$

Given volume of container A = twice the volume of container B.

$V_A=2V_B$

also the temperature is same for both the containers.

$T_A=T_B$

From Ideal gas equation we get

pV=nRT

$p_A{V}_A=p_B{V}_B$

As the container contains same liquid and temperature the term nRT will be same.

$\frac{p_A}{p_B}=\frac{V_B}{V_A}=\frac{V_B}{2V_B}=\frac{1}{2}$