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Question

# The variation of electric field between two charges q1 and q2 along the line joining the charges is plotted against the distance r from q1 (taking the direction from q1 to q2 as positive) as shown in the figure. Find the correct statement among the following is

A
q1 and q2 are positive and |q1|<|q2|
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B
q1 and q2 are positive and |q1|>|q2|
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C
q1 is positive and q2 is negative |q1|<|q2|
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D
q1 and q2 are negative and |q1|<|q2|
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Solution

## The correct option is C q1 is positive and q2 is negative |q1|<|q2|Just to the right of q1, →E is positive, so we can say that q1 is positive. Just to the left of q2, →E is negative, so we can say that q2 is negative. Let the distance between charges q1 and q2 be d and let x be the distance from q1 where net electric field is equal to zero. ∴kq1x2=kq2(d−x)2 ⇒∣∣∣q2q1∣∣∣=(d−x)2x2 Further, as →Enet=0 is close to q1, we can conclude that the magnitude of charge q2 must be greater than the magnitude of charge q1. So, |q2|>|q1| Hence, option (c) is the correct answer.

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