wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The variation of potential V with distance r from a fixed point is shown in the figure. The magnitude of electric field at r=2 cm is


A
200 V/m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
100 V/cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200 V/cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 200 V/m
The relation between electric field (E) and electric potential (V) is given by
E=dVdr
Here we can say that,
Electric field = Slope of the given graph between 0 to 2 cm

For 0 to 2 cm
dV=4 V0 V=4 V
and
dr=(20) cm=2 cm
dr=0.02 m
So,
E=40.02=200 V/m
The magnitude of electric field is 200 V/m

Hence, option (a) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Field and Potential Due to a Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon