The variation of the instantaneous current (I) and the instantaneous emf (E) in a circuit is as shown in fig. Which of the following statements is correct

The voltage lags behind the current by π/2

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The voltage leads the current by π/2

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The voltage and the current are in phase

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The voltage leads the current by π

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Solution

The correct option is B The voltage leads the current by π/2
At t = 0, phase of the voltage is zero, while phase of the current is $- \frac{π}{2}$ i.e., voltage leads by $\frac{π}{2}$

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E

E = 1.414 s i n (100 π t - \frac{π}{4})

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E = 1.414 s i n (100 π t - \frac{π}{4})

I = 0.707 s i n (100 π t)

E = 1.414 s i n (100 π t - \frac{π}{4})

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e = E_{0} sin (ω t - π / 6), i = I_{0} sin (ω t + π / 6)

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