The vector z=3−4i is turned anticlockwise through an angle of 180∘ and stretched 2.5 times. The complex number corresponding to the newly obtained vector is ....
A
−152+10i
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B
152+10i
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C
−152−10i
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D
152−10i
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Solution
The correct option is A−152+10i z=3−4i lie in fourth quadrant in complex plane, after turned anticlockwise through 1800this will lie in II quadrant, therefore, the number will be −3+4inow after stretching it 2.5 times i.e., multiplying by 2.5, the required complex number will be