The vectors a-b-c-b-c-a- and c-a-b- are

The correct option is C CoplanarSolving a⃗× ( b⃗×c⃗ )= ( a⃗ c⃗ )b⃗ ( a⃗ b⃗ )c⃗ #160;________1 b⃗× ( c⃗×a⃗ )= ( a⃗ b⃗ )c⃗ ( b⃗ c⃗ )a⃗ #160;___ ...

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Fallacy

The vectors ...

Question

The vectors $\to a \times (\to b \times \to c), \to b \times (\to c \times \to a)$ and $\to c \times (\to a \times \to b)$ are

Collinear

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Coplanar

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Like vectors

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Linearly independent

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Solution

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Similar questions

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

\to a, \to b, \to c

\to a \times \to b = \to c, \to b \times \to c = \to a, \to c \times \to a = \to b

| \to a | = | \to b | = | \to c |

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

| \to a \times \to b | + | \to b \times \to c | + | \to c \times \to a | =

\to a, \to b, \to c

| \to b | = | \to c |

(\to a + \to b) \times (\to a + \to c)} \times (\to b \times \to c) . (\to b + \to c) =

\to a, \to b, \to c

\to b \times \to c = \to a, \to c \times \to a = \to b

\to a \times \to b = \to c

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