Question

The velocity at the maximum height of projectile is half of its initial velocity projection. The angle of projection is

• A. ${30}^o$
• B. ${45}^o$
• C. ${60}^o$
• D. $76^o$

Answer 1

Answer: (C)

${60}^o$

Lets consider, $u=$ initial velocity of the projectile

$\theta =$ angle of projection

At maximum height,

$velocity=ucos\theta$

$\frac{u}{2}=ucos\theta$

$cos\theta =\frac{1}{2}=0.5$

$\theta =co{s}^{-1}\left(0.5\right)$

$\theta ={60}^0$

The correct option is C.