The velocity displacement graph of a particle moving along a straight line is shown in figure.
Then the acceleration displacement graph is.
A
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B
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C
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D
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Solution
The correct option is A As per the question from the graph, we can write υ=−x+2 a=dvdt=−dxdt=−υ υ=−(−x+2)=x−2
Therefore,
At x=0m we get, υ=0−2=−2m/s
At x=1m we get, υ=1−2=−1ms
At x=2m we get υ=2−2=0m/s
The velocity – displacement graph will be,
According to above calculations only (c) option justifies the equation.