The velocity of a body which starts from rest with an acceleration $2 m s^{- 2}$ and covering a distance of $10 m$ in $m s^{- 1}$ is:

\sqrt{98}

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\sqrt{40}

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\sqrt{20}

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\sqrt{12}

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Solution

The correct option is B $\sqrt{40}$
using the equations of motion ,
$v^{2} = u^{2} + 2 a s$
Intial velocity is zero.
$v^{2} = 2 \times 2 \times 10$
$v = \sqrt{40} m / s$

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