The velocity of a car traveling on a straight road is given by the equation $v = 9 + 8 t - t^{2}$ where $v$ is in meter per second and $t$ in second. The instantaneous acceleration when $t = 5 s$ is

2 m s^{- 2}

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1 m s^{- 2}

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- 1 m s^{- 2}

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- 2 m s^{- 2}

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Solution

The correct option is D $- 2 m s^{- 2}$
$v = 9 + 8 t - t^{2},$ Inst.acc $^{n}$ $= a = d v / d t = 8 - 2 t$
$∴$ instantaneous acceleration at $t = 5 s e c = 8 - 2 \times 5 = - 2 m / s^{2}$
$(D)$

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The velocity of a car traveling on a straight road is given by the equation v=9+8t−t2 where v is in meter per second and t in second. The instantaneous acceleration when t=5 s is

The correct option is D −2 ms−2v=9+8t−t2, Inst.accn =a=dv/dt=8−2t∴ instantaneous acceleration at t=5sec=8−2×5=−2m/s2(D)

The velocity of a car traveling on a straight road is given by the equation $v = 9 + 8 t - t^{2}$ where $v$ is in meter per second and $t$ in second. The instantaneous acceleration when $t = 5 s$ is

The correct option is D $- 2 m s^{- 2}$
$v = 9 + 8 t - t^{2},$ Inst.acc $^{n}$ $= a = d v / d t = 8 - 2 t$
$∴$ instantaneous acceleration at $t = 5 s e c = 8 - 2 \times 5 = - 2 m / s^{2}$
$(D)$