The velocity of a particle is given by v-a-bt-ct2- Where a-b-c are constants and t is the time then unit of b is

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Kinetic Friction

The velocity ...

Question

The velocity of a particle is given by $v = a + \frac{b}{t} + c t^{2}$ . Where a,b,c are constants and t is the time then unit of b is

m / s

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m

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m / s^{3}

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s e c

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Solution

The correct option is C $m$
Given,
$v = a + \frac{b}{t} + c t^{2}$

According to the principle of homogeneity,

Unit of $a =$ unit of $\frac{b}{t} =$ unit of $c t^{2} =$ unit of $v$

Unit of $v =$ unit of $\frac{b}{t}$

$\frac{m}{s} = \frac{b}{s}$

$b = m$
The correct option is B.

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The velocity of a particle is given by v=a+bt+ct2. Where a,b,c are constants and t is the time then unit of b is

The correct option is C mGiven,v=a+bt+ct2According to the principle of homogeneity,Unit of a= unit of bt=unit of ct2= unit of vUnit of v= unit of btms=bsb=mThe correct option is B.

The velocity of a particle is given by $v = a + \frac{b}{t} + c t^{2}$ . Where a,b,c are constants and t is the time then unit of b is

The correct option is C $m$
Given,
$v = a + \frac{b}{t} + c t^{2}$

According to the principle of homogeneity,

Unit of $a =$ unit of $\frac{b}{t} =$ unit of $c t^{2} =$ unit of $v$

Unit of $v =$ unit of $\frac{b}{t}$

$\frac{m}{s} = \frac{b}{s}$

$b = m$
The correct option is B.