The velocity of a particle is given by v-a-bt-ct2- Where a-b-c are constants and t is the time then unit of b is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Kinetic Friction

The velocity ...

Question

The velocity of a particle is given by $v = a + \frac{b}{t} + c t^{2}$ . Where a,b,c are constants and t is the time then unit of b is

m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

m / s^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $m$
Given,
$v = a + \frac{b}{t} + c t^{2}$

According to the principle of homogeneity,

Unit of $a =$ unit of $\frac{b}{t} =$ unit of $c t^{2} =$ unit of $v$

Unit of $v =$ unit of $\frac{b}{t}$

$\frac{m}{s} = \frac{b}{s}$

$b = m$
The correct option is B.

Suggest Corrections

Similar questions

The velocity $v$ of a particle at time $t$ is given by $v = a t + \frac{b}{t + c}$ where $a, b$ and $c$ are constants. The dimensions of $a, b$ and $c$ are respectively :

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

, where

a, b

and

c

are constants. The dimensions of

a, b

and

c

are respectively

Q. A particle starting from rest undergoes acceleration given by

a = | t - 2 | {m/s}^{2}

where,

t

is time in second. Velocity of particle after

4 sec

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

, where

a, b

and

c

are constant. The dimensions of

a, b

and

c

are respectively.

The velocity v of a particle at time t is given by v=at+ b/t+ c where a,b,c are constants . What will be the dimensions of a,b and c

Join BYJU'S Learning Program

The velocity of a particle is given by v=a+bt+ct2. Where a,b,c are constants and t is the time then unit of b is

The correct option is C mGiven,v=a+bt+ct2According to the principle of homogeneity,Unit of a= unit of bt=unit of ct2= unit of vUnit of v= unit of btms=bsb=mThe correct option is B.

The velocity of a particle is given by $v = a + \frac{b}{t} + c t^{2}$ . Where a,b,c are constants and t is the time then unit of b is

The correct option is C $m$
Given,
$v = a + \frac{b}{t} + c t^{2}$

According to the principle of homogeneity,

Unit of $a =$ unit of $\frac{b}{t} =$ unit of $c t^{2} =$ unit of $v$

Unit of $v =$ unit of $\frac{b}{t}$

$\frac{m}{s} = \frac{b}{s}$

$b = m$
The correct option is B.