The velocity of electron in third excited state of $B e^{3 +}$ will be:

\frac{3}{4} \times (2.188 \times 10^{8}) m s^{- 1}

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\frac{3}{4} \times (2.188 \times 10^{6}) m s^{- 1}

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(2.188 \times 10^{6}) k m s^{- 1}

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(2.188 \times 10^{3}) k m s^{- 1}

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Solution

The correct option is D $(2.188 \times 10^{3}) k m s^{- 1}$
Velocity of an electron in Bohr's orbit-

$V = \frac{2 π K e^{2}}{h} \times \frac{Z}{n} m s^{- 1}$

$V = 2.188 \times 10^{6} \times \frac{Z}{n} m s^{- 1}$

for $B e^{+ 3}, Z = 4, n = 4$ for $3^{r d}$ excite state

$V = 2.188 \times 10^{6} \times \frac{4}{4} m s^{- 1}$

$V = \frac{2.188 \times 10^{6}}{1000} \times \frac{4}{4} k m s^{- 1}$

$V = 2.188 \times 10^{3}$ Km/sec

Option D is correct.

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The velocity of electron in third excited state of Be3+ will be:

The correct option is D (2.188×103)kms−1Velocity of an electron in Bohr's orbit-V=2πKe2h×Znms−1V=2.188×106×Znms−1for Be+3,Z=4,n=4 for 3rd excite stateV=2.188×106×44ms−1V=2.188×1061000×44kms−1V=2.188×103 Km/secOption D is correct.

The velocity of electron in third excited state of $B e^{3 +}$ will be: