The velocity – time graph for two bodies A and B are shown. Then the acceleration of A and B are in the ratio

$s i n 25^{\circ} t o s i n 50^{\circ}$

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$t a n 25^{\circ} t o t a n 40^{\circ}$

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$c o s 25^{\circ} t o c o s 50^{\circ}$

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$t a n 25^{\circ} t o t a n 50^{\circ}$

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Solution

The correct option is D
$t a n 25^{\circ} t o t a n 50^{\circ}$

$a = slope of VT graph = t a n θ$

$R a t i o = \frac{t a n 25}{t a n 50}$

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The velocity – time graph for two bodies A and B are shown. Then the acceleration of A and B are in the ratio

The correct option is D tan 25∘ to tan 50∘ a = slope of VT graph =tanθ Ratio=tan 25tan 50

The correct option is D
$t a n 25^{\circ} t o t a n 50^{\circ}$

$a = slope of VT graph = t a n θ$

$R a t i o = \frac{t a n 25}{t a n 50}$