Question

The velocity time graph of particle moving along a straight line is shown in the figure in the time interval from t=$0$ t=$8$second answer the following three questions.

Answer 1

we know that

$velocity\times time=distance$

in velocity time graph area covered by velocity time gives the distance

hence

area covered $I$ triangle 1st I.e. $t=0tot=2sec$

so distance covered

$=2\times \frac{20}{2}$

$=20m$

2) $20\times 1+3\times 20+5\times 10$

$=20+60+50$

$=130m$