The velocity V of a body starting from rest and moving with uniform acceleration a is calculated by the formula V - - 2 a s - Here S represents the displacement- If error in measurement of acceleration is 4

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The velocity $V$ of a body starting from rest and moving with uniform acceleration a is calculated by the formula $V = \sqrt{2 a s}$ . Here $S$ represents the displacement. If error in measurement of acceleration is 4% and error in measurement of displacement is 2%, then the error in calculation of veiocity is

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Solution

The correct option is A 3%
$\begin{matrix} A c c o r d i n g t o q u e s t i o n . . . . . . . . . . . . . . . V = \sqrt{2 a s} e r r o r i n V = \frac{1}{2} (e r r o r i n a c c e l e r a t i o n + e r r o r i n d i s p l a c e m e n t) e r r o r i n V = \frac{1}{2} (4 + 2) ∴ e r r o r i n V = \frac{6}{2} = 3 p e r c e n t s o t h e c o r r e c t o p t i o n i s B . \end{matrix}$

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The velocity V of a body starting from rest and moving with uniform acceleration a is calculated by the formula V=√2as. Here S represents the displacement. If error in measurement of acceleration is 4% and error in measurement of displacement is 2%, then the error in calculation of veiocity is

The correct option is A 3%Accordingtoquestion...............V=√2aserrorinV=12(errorinacceleration+errorindisplacement)errorinV=12(4+2)∴errorinV=62=3percentsothecorrectoptionisB.