Question

The velocity $\left(v\right)$ of a particle moving along $x-$axis varies with its position $x$ as shown in figure. The acceleration $\left(a\right)$ of particle varies with position $\left(x\right)$ as

• A. $a^2=x+3$
• B. $a=2x^2+4$
• C. $2a=3x+5$
• D. $a=4x-8$

Answer 1

The correct option is D $a=4x-8$

As shown in the given figure

equation of velocity and displacement is

$V=-2x+4$

acceleration $a=V\frac{dv}{dx}=(-2x+4)(-2)=4x-8$