The velocitytime graph of a ball moving on the surface of a floor is given below.
Calculate the force acting on the ball, if the mass of the ball is 200 g.

1 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1 N
mass of ball is $m = 200 g = 0.2 k g$
acceleration of ball is slope of $a = \frac{d v}{d t} = \frac{20 - 0}{4 - 0} = 5 m / s^{2}$
$F o r c e = F = m a = 0.2 * 5 = 1 N$

Suggest Corrections

Similar questions

Q. Question 14
Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown in Figure given below. Calculate the acceleration and frictional force of the floor on the ball.

Q. Question 14
Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown in Figure given below. Calculate the acceleration and frictional force of the floor on the ball.

Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown. Calculate the frictional force of the floor on the ball.

A force of 10 N acts on a ball moving on a surface. The force of friction that must act between the surface of the ball and the surface so that the ball keeps on moving with constant velocity over the surface must be:

A ball is moving over a horizontal smooth surface with a constant velocity. What type of forces is acting on the ball?

Join BYJU'S Learning Program

The velocitytime graph of a ball moving on the surface of a floor is given below.Calculate the force acting on the ball, if the mass of the ball is 200 g.

The correct option is A 1 Nmass of ball is m=200g=0.2kgacceleration of ball is slope of a=dvdt=20−04−0=5m/s2Force=F=ma=0.2∗5=1N

The velocitytime graph of a ball moving on the surface of a floor is given below.
Calculate the force acting on the ball, if the mass of the ball is 200 g.

The correct option is A 1 N
mass of ball is $m = 200 g = 0.2 k g$
acceleration of ball is slope of $a = \frac{d v}{d t} = \frac{20 - 0}{4 - 0} = 5 m / s^{2}$
$F o r c e = F = m a = 0.2 * 5 = 1 N$