The vertex of the parabola represented by the quadratic equation $y = x^{2} + 2 x + 6$ is

(1,-6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-1,5)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1,-5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-1,6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B (-1,5)
Given equation $y = x^{2} + 2 x + 6$ can be written as:
$y = x^{2} + 2 x + 1 + 5 y - 5 = x^{2} + 2 x + 1 y - 5 = (x + 1)^{2}$
The vertex of a quadratic equation of the form $y - b = (x - a)^{2}$ is (a, b).

Comparing both the equations, a = -1, b = 5.

Suggest Corrections

Similar questions

y = x^{2} + 2 x + 6

y = x^{2} + 2 x + 6

y^{2} + 3 = 2 (2 x + y)

y - 2 x^{2} = 8 x + 5

(2 x - y - 3)^{2} = - 20 (x + 2 y - 4)

Join BYJU'S Learning Program