The voltage-current (V-I) graph of a metallic circuit at two different temperature $T_{1}$ and $T_{2}$ is shown, which of the temperature is higher? The answer is $T_{x}$ then x =

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Solution

We know slope of $V - I$ graph gives is resistance. Resistance of a material increases with increasing temperature.
In the given graph, $T_{2}$ has a higher slope, hence it mean it has higher
resistance and higher temperatures.
$T_{2} > T_{1}$

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The voltage-current (V-I) graph of a metallic circuit at two different temperature T1 and T2 is shown, which of the temperature is higher? The answer is Tx then x =

We know slope of V−I graph gives is resistance. Resistance of a material increases with increasing temperature.In the given graph, T2 has a higher slope, hence it mean it has higher resistance and higher temperatures.T2>T1

The voltage-current (V-I) graph of a metallic circuit at two different temperature $T_{1}$ and $T_{2}$ is shown, which of the temperature is higher? The answer is $T_{x}$ then x =

We know slope of $V - I$ graph gives is resistance. Resistance of a material increases with increasing temperature.
In the given graph, $T_{2}$ has a higher slope, hence it mean it has higher
resistance and higher temperatures.
$T_{2} > T_{1}$