Question

The volume (in litre) occupied by $40$ g of $C{H}_4$ at S.T.P, if its V.D. is $8$, will be $14X$. Then the value of $X$ is:

Answer 1

As we know,

Molar mass $=2\times vapourdensity=2\times 8=16gm$.

No. of moles $=\frac{40}{16}=2.5mol$

So, volume $=2.5\times 22.4=56litres$.

Hence, $X=4$.