The volume in ml of $0.1 M$ solution of $N a O H$ required to completely neutralize $100 m l$ of $0.3 M$ solution of $H_{3} P O_{3}$ is :

60

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600

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300

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30

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Solution

The correct option is B $600$

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Similar questions

20

0.1 M

(H_{3} P O_{3})

0.1

K O H

To neutralize completely 20 ml of 0.1 M aqueous solution of $H_{3} P O_{3}$ , the volume of 0.1 M aqueous KOH solution required is:

(H_{3} P O_{3}) .

H_{2} S O_{4}

(H_{3} P O_{3})

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