The volume occupied by 0.01 moles of helium gas at STP is:

0.224 l

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22.4 l

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2240 l

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2.24 l

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Solution

The correct option is A $0.224 l$
As 1 mole of a gaseous substance occupies 22.4 litre ( $22.4 l =$ gram molar volume)

Volume occupied $= G M V \times 0.01$ ( gram molar volume )

Hence, volume occupied $= 22.4 \times 0.01$
$= 0.224 l$

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