What volume is occupied by $2.5$ moles of helium gas at STP?

56 L

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14 L

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60 L

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45 L

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Solution

The correct option is A $56 L$
$1 m o l e$ of any gas at STP occupies volume $= 22.4 L$
Volume occupied by $2.5 m o l e s$ of helium gas $= 22.4 \times 2.5 = 56 L$

Hence, the correct option is $A$ .

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