The volume occupied by 1 mole atom of a diatomic gas at STP is:

22.4 L

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11.2 L

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5.6 L

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44.8 L

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Solution

The correct option is A 22.4 L
$M o l e = \frac{V o l u m e}{22.4} (A t S T P)$
So according to this formula 1 mole of gas occupies 22.4 litres at STP
Suppose diatomic gas is $O_{2}$
So,
1 mole of $O_{2}$ gas occupies 22.4 litres at STP

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Similar questions

22.4

Volume occupied by 1 mole of a gas at STP is 22.7L or 22.4L?

As internet is showing it 22.4L and our school is teaching it 22.7L.

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