Question

The volume of $0.1NHN{O}_3$ solution that can be prepared from $6.3gm$ of $HN{O}_3$ is:

• A. $1lit$
• B. $1.5lit$
• C. $2lit$
• D. $3lit$

Answer 1

Answer: (A)

$1lit$

Given, Normality $N=0.1N$ Weight= $6.3g$

We know that $N=\frac{WA}{MA}\times \frac{1000}{V}$

So, $0.1=\frac{6.3}{630}\times \frac{1000}{V}$

$\Rightarrow 0.1=\frac{100}{V}$

$\Rightarrow V=\frac{1100}{0.1}=1000ml=1Litre$

Hence, volume required is $1L$ .