The volume of $0.5 M$ aqueous $N a O H$ solution required to neutralize $10 m l$ of $2 M$ aqueous HCl solution is:

20 m l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 m l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

80 m l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

120 m l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $40 m l$
$N a O H + H C l ⟶ N a C l + H_{2} O$

$0.5 M$ $2 M$

$V_{2} = 10 m l, V_{1} = ?$

$M_{1} V_{1} = M_{2} V_{2}$ ----- [Since n-factor is 1 in both the cases]

$\Rightarrow 0.5 V_{1} = 2 \times 10$

$\Rightarrow V_{1} = \frac{2}{0.5} \times 10$

$\Rightarrow V_{1} = 40 m L$

Hence, the correct option is B.

Suggest Corrections

Similar questions

To neutralize completely 20 ml of 0.1 M aqueous solution of $H_{3} P O_{3}$ , the volume of 0.1 M aqueous KOH solution required is:

(H_{3} P O_{3}) .

(C_{2} H_{2} O_{4} .2 H_{2} O)

N a O H

To neutralise completely 20 ml of 0.1 M of aqueous solution of phosphoric acid the volume of 0.1 M aqueous KOH solution required is ??

To neutralize completely 20 mL of 0.1molar aqueous of H₃PO₄,what volume of 0.1M KOH solution will be required?

Join BYJU'S Learning Program