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Question

The volume of 10 N and 4N HCI required to make 1 L of 7 N HCL are
  1. 0.5 L of 10 N HCI and 0.5 L of 4N HCI
  2. 0.6L of 10 N HCI of 0.4 L of 4N HCI
  3. 0.75 L of 10 N HCI of 0.25 L of 4N HCI
  4. 0.8 L of 10 N HCI & 0.2 L of 4 N HCI


Solution

The correct option is A 0.5 L of 10 N HCI and 0.5 L of 4N HCI
N1V1+N2V2=NV
Where V1+V2=1L
Or V2=(1V1)L
10×V1+4(1V1)=1×7
10V1+44V1=7
6V1=3
V1=36=0.5 L
V2=0.5 L

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