Question

The volume of 3 N $HCl$ required to prepare 500 mL of an aqueous solution of 2 N $HCl$ is:

• A. 750 mL
• B. 150 mL
• C. 333.33 mL
• D. 233.33 mL

Answer 1

The correct option is C 333.33 mL

Let the volume of 3 M $HCl$ solution be V mL.
Since, normality becomes equal to molarity for $HCl$.
$M_1{V}_1=M_2{V}_2(3\times V)=(2\times 500)$
$\Rightarrow V=333.33$ mL
Volume of 3 M solution required = 333.33 mL