The volume of a gas at constant pressure increases by 2% when the temperature is increased by 5 $^{0}$ K, It's initial temperature is

100

^{0}

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250

^{0}

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500

^{0}

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1000

^{0}

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Solution

The correct option is C 250 $^{0}$ K
$T_{1} = T$ , $T_{2} = T + 5$
$V_{1} = V$ and $V_{2}$ $=$ $\frac{102 \times V}{100}$
$\frac{V_{1}}{T_{1}}$ $=$ $\frac{V_{2}}{T_{2}}$
$\frac{T_{2}}{T_{1}}$ $=$ $\frac{V_{2}}{V_{1}}$
$\frac{T + 5}{T}$ $=$ $\frac{102}{100}$ $=$ $1.02$
$T + 5$ $=$ $1.02 T$

$0.02 T = 5$

$T = 250^{0} K$

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The volume of a gas at constant pressure increases by 2% when the temperature is increased by 50 K, It's initial temperature is

The correct option is C 2500 KT1=T, T2=T+5V1=V and V2 = 102×V100V1T1 = V2T2 T2T1 = V2V1T+5T = 102100 = 1.02T+5 = 1.02T0.02T=5T=2500K

The volume of a gas at constant pressure increases by 2% when the temperature is increased by 5 $^{0}$ K, It's initial temperature is