The volume of a gas at NTP is 100 ml- What will be the volume of the gas at 27- Cl and 380 mm pressure-A- 760 mlB- 100 mlC- 200 mlD- 219-78 ml

The correct option is D 219.78 mlAccording to General Gas Equation P_1V_1/T_1=P_2V_2/T_2⇒760× 100/273=380× V_2/300 ⇒ V_2=760× 100× 300/380× 273=219.78ml ...

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Standard XII

Physics

Ideal Gas Equation

The volume of...

Question

The volume of a gas at NTP is 100 ml. What will be the volume of the gas at$27^{\circ}C$ and 380 mm pressure?

100 ml

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760 ml

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219.78 ml

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200 ml

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Solution

The correct option is C 219.78 ml
According to General Gas Equation
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} \Rightarrow \frac{760 \times 100}{273} = \frac{380 \times V_{2}}{300}$
$\Rightarrow V_{2} = \frac{760 \times 100 \times 300}{380 \times 273} = 219.78 m l$

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The volume of a gas at NTP is 100 ml. What will be the volume of the gas at\(27^{\circ}C\) and 380 mm pressure?

The correct option is C 219.78 mlAccording to General Gas Equation P1V1T1=P2V2T2⇒760×100273=380×V2300 ⇒V2=760×100×300380×273=219.78ml

The correct option is C 219.78 ml
According to General Gas Equation
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} \Rightarrow \frac{760 \times 100}{273} = \frac{380 \times V_{2}}{300}$
$\Rightarrow V_{2} = \frac{760 \times 100 \times 300}{380 \times 273} = 219.78 m l$