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Stoichiometric Calculations

The volume of...

Question

The volume of $C O_{2}$ obtained at STP by the decompostion of 10 g of calcium carbonate is:
(molar mass of calcium carbonate = 100 $g m o l^{- 1}$

2.24 L

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44.8 L

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67.2 L

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22.4 L

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Solution

The correct option is A 2.24 L
The balanced chemical equation is:
$C a C O_{3} \to C a O + C O_{2}$

Given mass of calcium carbonate = 10 g
Moles of calcium carbonate = $\frac{10}{100} = 0.1$
Moles of $C O_{2}$ that can be obtained according to stoichiometry = 0.1
As, 1 mole of $C O_{2}$ corresponds to 22.4 L at STP.
$∴$ 0.1 mole of $C O_{2}$ corresponds to 2.24 L at STP

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