The volume of CO2 evolved at STP on heating 50 gram of calcium carbonate
Step 1: The chemical equation for the given reaction is:
CaCO3⟶CaO+CO2
Molar mass of CaCO3 = 100 g
Molar mass of CaO = 56 g
Molar mass of CO2 = 44 g
Step 2: According to reaction, 1 mole of CaCO3 produces 1 mole of CO2
100 grams of CaCO3 produces 44 grams of CO2
∴ 50 g of CaCO3 produces 44100×50=22g