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Question

The volume of CO2 evolved at STP on heating 50 gram of calcium carbonate

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Solution

Step 1: The chemical equation for the given reaction is:

CaCO3CaO+CO2

Molar mass of CaCO3 = 100 g

Molar mass of CaO = 56 g

Molar mass of CO2 = 44 g

Step 2: According to reaction, 1 mole of CaCO3 produces 1 mole of CO2

100 grams of CaCO3 produces 44 grams of CO2

50 g of CaCO3 produces 44100×50=22g


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