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Byju's Answer
Standard X
Chemistry
Mole Concept
The volume of...
Question
The volume of gas at NTP produced by
100
g of
C
a
C
2
with water is :
C
a
C
2
+
H
2
O
→
C
a
(
O
H
)
2
+
C
2
H
2
A
70 L
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B
35 L
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C
17.5 L
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D
22.4 L
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Solution
The correct option is
B
35 L
C
a
C
2
+
2
H
2
O
→
C
a
(
O
H
)
2
+
C
2
H
2
Number of moles =
100
64
Volume =
100
64
×
22.4
=
35
L.
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0
Similar questions
Q.
Formation of polyethylene from calcium carbide takes place as given below:
C
a
C
2
+
2
H
2
O
→
C
a
(
O
H
)
2
+
C
2
H
2
C
2
H
2
+
H
2
→
C
2
H
4
n
C
2
H
4
→
(
−
C
H
2
−
C
H
2
−
)
n
The amount (in kg) of polyethylene obtained from
64.1
kg of
C
a
C
2
is
Q.
C
a
C
2
+
H
2
O
→
C
2
H
2
+
C
a
(
O
H
)
2
The reaction of calcium carbide and water produces acetylene gas (
C
2
H
2
) and calcium hydroxide.
What volume of
C
2
H
2
will form from
0.200
m
o
l
C
a
C
2
which reacts with an excess of water? Assume the gas will be at STP conditions.
Q.
Acetylene, used as a fuel in welding torches, is produced in a reaction between calcium carbide and water:
C
a
C
2
+
2
H
2
O
→
C
a
(
O
H
)
2
+
C
2
H
2
How many grams of
C
2
H
2
are formed from 0.400 moles of
C
a
C
2
?
Q.
Polyethylene can be produced from
C
a
C
2
according to the following sequence of reactions.
C
a
C
2
+
H
2
O
→
C
a
O
+
C
2
H
2
(Yield = 70 %)
C
2
H
2
+
H
2
→
C
2
H
4
(Yield = 50 %)
n
C
2
H
4
→
(
C
H
2
C
H
2
)
n
(Yield = 20 %)
Calculate the mass of polyethylene which can be produced from
20
kg
of
C
a
C
2
.
Q.
Formation of polyethylene from calcium carbide taken place as follows:
C
a
C
2
+
2
H
2
O
→
C
a
(
O
H
)
2
+
C
2
H
2
C
2
H
2
+
H
2
→
C
2
H
4
n
C
2
H
4
→
(
C
H
2
−
C
H
2
)
n
The amount of polyethylene obtained from 64.0 kg of
C
a
C
2
is:
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