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Question

The volume of oxygen liberated at STP from 15 mL of 20 volume H2O2 is:

A
250 mL
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B
300 mL
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C
150 mL
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D
200 mL
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Solution

The correct option is B 300 mL
1 L of 20 volume of H2O2 will give 20 L of oxygen at NTP.

Oxygen liberated from 1000 mL (1 L) of H2O2 = 20 L

Oxygen liberated from 15 mL of H2O2 = 201000×15 = 0.3 L = 300 mL

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