The volume $V$ of a gas varies directly as its absolute temperature $T$ and inversely as its pressure $P$ , when $P = 20$ and $T = 300, V = 50$ . If $P = 25$ and $T = 450$ , then $V$ must be

50

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55

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60

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65

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Solution

The correct option is B $60$
$V α \frac{T}{P}$
$V = \frac{K T}{P}$
when $V = 50$
$T = 300$
$P = 20$
$50 = \frac{K \times 300}{20}$
$K = \frac{10}{3}$
when $P = 25$ , $T = 450$ ,
$V = \frac{10}{3} \times \frac{450}{25} = 60$

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The volume V of a gas varies directly as its absolute temperature T and inversely as its pressure P, when P=20 and T=300,V=50. If P=25 and T=450, then V must be

The correct option is B 60VαTPV=KTPwhen V=50 T=300 P=2050=K×30020K=103when P=25, T=450, V=103×45025=60

The volume $V$ of a gas varies directly as its absolute temperature $T$ and inversely as its pressure $P$ , when $P = 20$ and $T = 300, V = 50$ . If $P = 25$ and $T = 450$ , then $V$ must be

The correct option is B $60$
$V α \frac{T}{P}$
$V = \frac{K T}{P}$
when $V = 50$
$T = 300$
$P = 20$
$50 = \frac{K \times 300}{20}$
$K = \frac{10}{3}$
when $P = 25$ , $T = 450$ ,
$V = \frac{10}{3} \times \frac{450}{25} = 60$