The volumes of two HCl solution A (0.5 N) and B (0.1 N) to be mixed for preparing 2 L of 0.2 N HCl are:

0.5 L of A + 1.5 L of B

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1.5 L of A + 0.5 L of B

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1 L of A + 1 L of B

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0.75 L of A + 1.25 L of B

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Solution

The correct option is A 0.5 L of A + 1.5 L of B
Let x L of A and (2-x)L of B are mixed.

$M_{1} V_{1} + M_{2} V_{2} = M_{R} (V_{1} + V_{2})$

$0.5 \times x + 0.1 (2 - x) = 0.2 \times 2$

$(0.5 - 0.1) x = 0.4 - 0.2$

$0.4 x = 0.2$

$x = 0.5 L$

$∴ 0.5 L$ of A and 1.5 L of B should be mixed.

Hence, the correct option is $A$

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The volumes of two HCl solution A (0.5 N) and B (0.1 N) to be mixed for preparing 2 L of 0.2 N HCl are:

The correct option is A 0.5 L of A + 1.5 L of BLet x L of A and (2-x)L of B are mixed.M1V1+M2V2=MR(V1+V2)0.5×x+0.1(2−x)=0.2×2(0.5−0.1)x=0.4−0.20.4x=0.2x=0.5L∴0.5L of A and 1.5 L of B should be mixed.Hence, the correct option is A