The water level in a well is at a depth of 125 m. If the acceleration due to gravity is $10 m s^{- 2}$ and a boy gently drops a stone, he hears the sound of splash in 5.35 s. The speed of sound is ..........

300 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

320 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

368 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

357 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $357 m s^{- 1}$
Answer is D.

The time taken for the stone to hit the waterr is given as $S = u t + \frac{1}{2 t} a t^{2}$ .
That is, $125 = 0 \times t + \frac{1}{2} \times 10 \times t^{2}$
So, $t^{2} = 25, t = 5$ .
Therefore, the time in which the sound travels 125 m = (5.35 - 5)s = 0.33 s.
Hence, the speed of sound = Distance/time = 125 m/0.33 s = 357.1 m/s.
The speed of sound is 357 m/s.

Suggest Corrections

Similar questions

Tinku dropped a stone into a very deep well. He hears the sound 6.53 s after he dropped the stone. Find the depth of the well. Take acceleration due to gravity, g =10 $m s^{- 2}$ and $v_{s o u n d}$ = 340 $m s^{- 1}$ .

Tinku dropped a stone into a very deep well. He hears the sound $6.53 s$ after he dropped the stone. Find the depth of the well. Take acceleration due to gravity, $g = 10 m s^{- 2}$ and $v_{s o u n d} = 340 m s^{- 1}$ .

Tinku dropped a stone into a very deep well.He hears the sound 6.53s after he dropped the stone. Find the depth of the well. Take acceleration due to gravity,g=10m/s² and v sound = 340m/s.

Q. A person measures the depth of a well by measuring the time interval between dropping a stone and receiving the sound of impact with the bottom of the well. The error in his measurement of time is