The wave function - of 2s is given by-2s - 12-2 - 1a0 12 2-ra0e-r2a0At r-r0- radial node is formed- Thus for 2s- r0 in terms of a0 is-

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Standard XIII

Chemistry

Shapes of Orbitals and Nodes

The wave func...

Question

The wave function $(Ψ)$ of $2 s$ is given by:
$Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- \frac{r}{2 a_{0}}}$
At $r = r_{0}$ , radial node is formed. Thus for $2 s$ , $r_{0}$ in terms of $a_{0}$ is:

r_{0} = a_{0}

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r_{0} = 2 a_{0}

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r_{0} = \frac{a_{0}}{2}

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r_{0} = 4 a_{0}

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Solution

The correct option is B $r_{0} = 2 a_{0}$
At the node, probability of finding an electron is zero. So, the wave function becomes zero.
When $r = r_{0}, ψ_{2 s} = 0$ , then from the given equation:
$2 - \frac{r}{a_{0}} = 0$
$r = 2 a_{0}$

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Similar questions

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- r / 2 a_{0}}

r = r_{0}

radial node is formed. Thus for

2 s

r_{0}

in terms of

a_{0}

is:

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- \frac{r}{2 a_{0}}}

r = r_{0}

, radial node is formed. Thus for

2 s

r_{0}

in terms of

a_{0}

is:

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{(- r / a_{0})}

Where

a_{0}

is Bohr's radius. If the radial node in

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is at

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then find

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in terms of

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Q. The wave function

(Ψ)

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Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{(- r / a_{0})}

Where

a_{0}

is Bohr's radius. If the radial node in

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then find

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Q. The Schrondinger equation for hydrogen atom is

ψ = \frac{1}{4 \sqrt{2 π}} (\frac{1}{a_{0}})^{\frac{3}{2}} (2 - \frac{r_{0}}{a_{0}}) e^{-} \frac{r_{0}}{a_{0}}

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The wave function (Ψ) of 2s is given by: Ψ2s=12√2π(1a0)12{2−ra0}e−r2a0 At r=r0, radial node is formed. Thus for 2s, r0 in terms of a0 is:

The correct option is B r0=2a0At the node, probability of finding an electron is zero. So, the wave function becomes zero. When r=r0, ψ2s=0, then from the given equation: 2−ra0=0 r=2a0

The wave function $(Ψ)$ of $2 s$ is given by:
$Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- \frac{r}{2 a_{0}}}$
At $r = r_{0}$ , radial node is formed. Thus for $2 s$ , $r_{0}$ in terms of $a_{0}$ is:

The correct option is B $r_{0} = 2 a_{0}$
At the node, probability of finding an electron is zero. So, the wave function becomes zero.
When $r = r_{0}, ψ_{2 s} = 0$ , then from the given equation:
$2 - \frac{r}{a_{0}} = 0$
$r = 2 a_{0}$