Question

The wavelength of radiation emitted is ${\lambda }_0$ when an electron in hydrogen atom jumps from 3rd to 2nd orbit. If in the hydrogen atom itself, the electron jumps from fifth orbit to second orbit, then the wavelength of emitted radiation will be:

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$\frac{{\lambda }^{\prime }}{{\lambda }_0}=\frac{\frac{1}{2^2}-\frac{1}{3^2}}{\frac{1}{2^2}-\frac{1}{5^2}}$